(x^2+2i)(x^2-2i)=0

Solution for (x^2+2i)(x^2-2i)=0 equation:

Simplifying
(x2 + 2i)(x2 + -2i) = 0

Reorder the terms:
(2i + x2)(x2 + -2i) = 0

Reorder the terms:
(2i + x2)(-2i + x2) = 0

Multiply (2i + x2) * (-2i + x2)
(2i * (-2i + x2) + x2(-2i + x2)) = 0
((-2i * 2i + x2 * 2i) + x2(-2i + x2)) = 0

Reorder the terms:
((2ix2 + -4i2) + x2(-2i + x2)) = 0
((2ix2 + -4i2) + x2(-2i + x2)) = 0
(2ix2 + -4i2 + (-2i * x2 + x2 * x2)) = 0
(2ix2 + -4i2 + (-2ix2 + x4)) = 0

Reorder the terms:
(2ix2 + -2ix2 + -4i2 + x4) = 0

Combine like terms: 2ix2 + -2ix2 = 0
(0 + -4i2 + x4) = 0
(-4i2 + x4) = 0

Solving
-4i2 + x4 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1x4' to each side of the equation.
-4i2 + x4 + -1x4 = 0 + -1x4

Combine like terms: x4 + -1x4 = 0
-4i2 + 0 = 0 + -1x4
-4i2 = 0 + -1x4
Remove the zero:
-4i2 = -1x4

Divide each side by '-4'.
i2 = 0.25x4

Simplifying
i2 = 0.25x4

Take the square root of each side:
i = {-0.5x2, 0.5x2}